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In a vernier callipers, 1 cm on the main scale is divided into 20 equal parts. If 50 divisions of the vernier scale coincide with 49 divisions of the main scale, the least count of the instrument is :

Options

  1. A0.001 cm
  2. B0.002 cm
  3. C0.02 cm
  4. D0.05 cm

Correct answer

A. 0.001 cm

Step-by-step solution

Value of one main scale division (MSD) = 1 20 cm = 0.05 cm. Given that 50 vernier scale divisions (VSD) coincide with 49 main scale divisions (MSD). 50 VSD = 49 MSD 1 VSD = 49 50 MSD Least count (LC) = 1 MSD - 1 VSD LC = 1 MSD - 49 50 MSD = 1 50 MSD LC = 1 50 0.05 cm = 0.001 cm. Answer: 0.001 cm

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