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NEET2026PhysicsChapterActual

A uniform metallic wire having a total resistance of 12 is bent to form an equilateral triangle PQR. A separate resistor of 3 is connected between the vertex P and the midpoint S of the side QR. A battery of 6 V is connected across points P and Q as shown in the figure. The total current ( I ) drawn from the battery is :

Options

  1. A2 A
  2. B2.5 A
  3. C3 A
  4. D1.5 A

Correct answer

C. 3 A

Step-by-step solution

The total resistance of the uniform metallic wire is 12 . Since it is bent into an equilateral triangle PQR, the resistance of each side is: R_ PQ = R_ QR = R_ PR = 12 3 = 4 Point S is the midpoint of side QR, so the resistance of the segments QS and SR will be half of R_ QR : R_ QS = R_ SR = 4 2 = 2 A separate resistor of 3 is connected between P and S. Let's simplify the circuit to find the equivalent resistance across the battery terminals P and Q. 1. The resistors in branches PR and SR are in series because nod

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