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NEET2026PhysicsChapterActual

A moving coil galvanometer has a coil resistance of 49.9 and requires a current of 10 mA for full-scale deflection. If a shunt resistor of 0.1 is connected in parallel with the galvanometer, what is the maximum current that this modified instrument can measure?

Options

  1. A0.5 A
  2. B4.99 A
  3. C5 A
  4. D50 A

Correct answer

C. 5 A

Step-by-step solution

The maximum current I that the modified instrument can measure is determined by equating the potential difference across the galvanometer and the shunt resistor. I_g G = (I - I_g) S Substituting the given values I_g = 10 mA = 0.01 A , G = 49.9 , and S = 0.1 : 0.01 49.9 = (I - 0.01) 0.1 0.499 = 0.1 I - 0.001 0.1 I = 0.5 I = 5 A Answer: 5 A

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