A capacitor of capacitance 50 F is connected to an alternating source of voltage given by V = 100 (100 t) + 100 (100 t) V. The RMS value of the current in the circuit is:

Step-by-step solution

The given voltage equation is V = 100 (100 t) + 100 (100 t) V. This can be simplified by combining the sine and cosine terms. The peak voltage V_m is the resultant of the two orthogonal components: V_m = 100^2 + 100^2 = 100 2 V The RMS voltage is: V_ rms = V_m 2 = 100 2 2 = 100 V The angular frequency is = 100 rad/s. The RMS current in the capacitive circuit is given by: I_ rms = V_ rms X_C = V_ rms C Substituting the values: I_ rms = 100 100 (50 10⁻⁶) I_ rms = 10000 50 10⁻⁶ = 0.5 A Answer: 0.5 A