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JEE MainPhysicsKinetic Theory of Gases

An ideal gas undergoes a thermodynamic process such that its volume expansion coefficient varies with absolute temperature T as = 2 T . The process equation for the gas in terms of pressure P and volume V is :

Options

  1. AP V^2 = constant
  2. BP V⁻¹ = constant
  3. CP V^ 3/2 = constant
  4. DP^2 V = constant

Correct answer

D. P^2 V = constant

Step-by-step solution

The volume expansion coefficient is defined as = 1 V dV dT . Given that = 2 T , we can write: 1 V dV dT = 2 T Integrating both sides: dV V = 2 T dT V = 2 T + C V = (T^2) + C V = k T^2 T = V k Using the ideal gas equation, PV = nRT : P = nRT V Substituting the expression for T : P = nR V V k = nR k V^ -1/2 P V^ 1/2 = constant Squaring both sides, we get the process equation: P^2 V = constant Answer: P^2 V = constant

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