JEE MainMathematicsVector Algebra
Let a vector a be coplanar with the vectors b = 3 i + 4 j and c = 8 i + 6 k . If the projection of a on b is equal to the projection of a on c , and the projection of a on the vector d = i - j + k is 2 3 , then a is equal to:
Options
- A14 i + 8 j + 6 k
- B6 13 (11 i + 4 j + 6 k )
- C7 i + 4 j + 3 k
- D1 3 (7 i + 4 j + 3 k )
Correct answer
C. 7 i + 4 j + 3 k
Step-by-step solution
Since a is coplanar with b and c , we can write a = x b + y c . The condition that the projection of a on b equals the projection of a on c gives: a b | b | = a c | c | We calculate the necessary dot products and magnitudes: | b | = 3^2 + 4^2 = 5 | c | = 8^2 + 6^2 = 10 b b = 25 c c = 100 b c = (3)(8) + (4)(0) + (0)(6) = 24 Substituting a = x b + y c into the projection equality: x( b b ) + y( b c ) 5 = x( b c ) + y( c c ) 10 25x + 24y 5 = 24x + 100y 10 2(25x + 24y) = 24x + 100y 50x + 48y = 24x + 100y 26x = 52y x =