The time period of revolution of an electron in the second stationary orbit of Bohr's hydrogen atom is T . The time period of revolution of the electron in the third stationary orbit will be:

Step-by-step solution

In Bohr's model of the hydrogen atom, the time period of revolution of an electron in the n^ th orbit is given by T_n = 2 r_n v_n . Since the radius r_n n^2 and the orbital speed v_n 1 n , the time period T_n is proportional to n^3 . T_n n^3 Taking the ratio of the time periods for the third and second orbits: T₃ T₂ = 3^3 2^3 = 27 8 Given that T₂ = T , we get: T₃ = 27 8 T Answer: 27 8 T