JEE MainMathematicsVector Algebra
Let S be the set of all a R for which the angle between the vectors p = a i - j + k and q = i + a j - 3 k is acute for at least one value of [0, ] . Then S is equal to
Options
- A(- , -12) ( 3 2 , )
- B(- , -12) (0, )
- C( 3 2 , )
Correct answer
A. (- , -12) ( 3 2 , )
Step-by-step solution
For the angle between p and q to be acute, their dot product must be strictly positive. p q > 0 (a )( ) + (-1)(a ) + (1)(-3) > 0 a ^2 - a - 3 > 0 Let t = . Since [0, ] , we have t [-1, 1] . The condition becomes f(t) = at^2 - at - 3 > 0 for at least one t [-1, 1] . This requires the maximum value of f(t) on [-1, 1] to be strictly positive. Case 1: a > 0 The parabola opens upwards. The vertex is at t = -(-a) 2a = 1 2 . The maximum value on [-1, 1] occurs at the point furthest from the vertex, which is t = -1 . f(-1)