A particle of mass 4 kg moves along a straight line. The velocity v of the particle at various positions x is recorded in the table below: x (m) 0 1 2 3 v (m/s) 2 4 6 8 The work done by the net force on the particle during the displacement from x = 1 m to x = 3 m is:

Step-by-step solution

From the given table, the initial velocity of the particle at x = 1 m is v_i = 4 m/s. The final velocity at x = 3 m is v_f = 8 m/s. According to the work-energy theorem, the work done by the net force is equal to the change in kinetic energy: W = K = 1 2 m (v_f^2 - v_i^2) Substituting the given values ( m = 4 kg): W = 1 2 4 (8^2 - 4^2) W = 2 (64 - 16) = 2 48 = 96 J. Answer: 96 J