Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE MainMathematicsPermutation and Combination

Five-digit numbers are formed using the digits 1, 2, 3, , 9 without repetition. The total number of such five-digit numbers, in which either the first three digits are consecutive integers in increasing order or the last three digits are consecutive integers in increasing order, is

Correct answer

415

Step-by-step solution

Let the five-digit number be d₁ d₂ d₃ d₄ d₅ . Let A be the set of numbers where the first three digits d₁, d₂, d₃ are consecutive integers in increasing order. The possible consecutive blocks of three digits from 1, 2, , 9 are (1,2,3), (2,3,4), , (7,8,9) . There are 7 such blocks. For each block, the remaining 2 positions can be filled by the remaining 6 digits in ⁶P₂ = 30 ways. Thus, n(A) = 7 30 = 210 . Let B be the set of numbers where the last three digits d₃, d₄, d₅ are consecutive integers in increasing order.

Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list All JEE Main PYQs