A proton and an particle are accelerated from rest through different potential differences such that they acquire the same linear momentum. The ratio of the accelerating potential of the proton to that of the particle is :

Question

Quantrex Academy · Accepted Answer

Correct answer: C. 8:1

For a charged particle accelerated from rest through a potential difference V , the linear momentum acquired is given by p = 2mqV . Given that both particles acquire the same linear momentum, we have: p_p = p_ 2m_pq_pV_p = 2m_ q_ V_ Squaring both sides: m_pq_pV_p = m_ q_ V_ The ratio of their accelerating potentials is: V_p V_ = m_ q_ m_p q_p We know that for an particle, m_ = 4m_p and q_ = 2q_p . Substituting these values: V_p V_ = 4m_p 2q_p m_p q_p = 8 Thus, the required ratio is 8:1 . Answer: 8:1

A proton and an particle are accelerated from rest through different potential differences such that they acquire the same linear momentum. The ratio of the accelerating potential of the proton to that of the particle is :

Options

Correct answer

Step-by-step solution

More from Dual Nature of Matter