A block of mass 20 kg is pushed along a horizontal floor for a distance of 5 m . If the total work done against friction during this displacement is 250 J , the coefficient of kinetic friction between the block and the floor is: (Take g = 10 m/s ^2 )

Step-by-step solution

Given: Mass of the block, m = 20 kg Distance moved, d = 5 m Work done against friction, W = 250 J The work done against friction is given by the formula: W = f_k d = _k m g d Rearranging for the coefficient of kinetic friction _k : _k = W m g d Substituting the given values: _k = 250 20 10 5 _k = 250 1000 = 0.25 Answer: 0.25