An electromagnetic wave is described by the electric field E = E₀ ( 10¹⁵ t) (3 10¹⁵ t) (in SI units). When this wave is incident on a metal surface, the stopping potential for the emitted photoelectrons is found to be 5.0 V. The work function of the metal is: (Given: Planck's constant h = 4.14 10⁻¹⁵ eV s)

Step-by-step solution

The given electric field is E = E₀ ( 10¹⁵ t) (3 10¹⁵ t) . Using the trigonometric identity 2 A B = (A+B) + (A-B) , we can rewrite the electric field as: E = E₀ 2 [ (4 10¹⁵ t) + (2 10¹⁵ t)] This indicates that the wave consists of two frequency components with angular frequencies: ₁ = 4 10¹⁵ rad/s ₂ = 2 10¹⁵ rad/s The maximum kinetic energy of the photoelectrons is determined by the highest frequency component, which is ₁ = 4 10¹⁵ rad/s. The corresponding frequency is = ₁ 2 = 2 10¹⁵ Hz. The energy of the incident ph