JEE MainPhysicsKinetic Theory of Gases
Two different ideal gases, A and B , are kept in separate containers. The most probable speed of the molecules in gas A is equal to the root mean square speed of the molecules in gas B . If the average translational kinetic energy per molecule of gas A is twice that of gas B , then the ratio of the molar mass of gas A to that of gas B ( M_A M_B ) is
Options
- A3 4
- B4 3
- C2 3
- D2
Correct answer
B. 4 3
Step-by-step solution
The average translational kinetic energy per molecule of an ideal gas depends only on its absolute temperature T and is given by E = 3 2 kT . Given that E_A = 2E_B , we have: 3 2 kT_A = 2 ( 3 2 kT_B ) T_A = 2T_B The most probable speed of molecules in gas A is v_ mp,A = 2RT_A M_A . The root mean square speed of molecules in gas B is v_ rms,B = 3RT_B M_B . According to the given condition, v_ mp,A = v_ rms,B : 2RT_A M_A = 3RT_B M_B Squaring both sides: 2T_A M_A = 3T_B M_B Substitute T_A = 2T_B into the equation: 2(2