A hydrogen atom in its ground state is excited such that the angular momentum of its electron increases by 2.10 10⁻³⁴ J s . The energy absorbed by the atom is (Given Planck's constant h = 6.6 10⁻³⁴ J s ):

Step-by-step solution

Given, increase in angular momentum L = 2.10 10⁻³⁴ J s . We know that the change in angular momentum is given by: L = (n₂ - n₁) h 2 Substituting the given values: 2.10 10⁻³⁴ = (n₂ - 1) 6.6 10⁻³⁴ 2 Since h 2 1.05 10⁻³⁴ J s , we have: n₂ - 1 = 2.10 10⁻³⁴ 1.05 10⁻³⁴ = 2 n₂ = 3 The energy absorbed by the hydrogen atom to transition from n = 1 to n = 3 is: E = 13.6 ( 1 1^2 - 1 3^2 ) eV E = 13.6 8 9 eV 12.09 eV Answer: 12.09 eV