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JEE MainPhysicsDual Nature of Matter

Light of angular frequency 2 10¹⁵ rad/s is incident on a metallic surface. If the maximum kinetic energy of the emitted photoelectrons is 1.14 eV, the work function of the metal is closest to: (Take h = 4.14 10⁻¹⁵ eV.s)

Options

  1. A5.28 eV
  2. B4.14 eV
  3. C3.00 eV
  4. D24.86 eV

Correct answer

C. 3.00 eV

Step-by-step solution

The angular frequency of the incident light is = 2 10¹⁵ rad/s. The linear frequency is given by: = 2 = 2 10¹⁵ 2 = 10¹⁵ Hz The energy of the incident photon is: E = h = (4.14 10⁻¹⁵ eV.s ) (10¹⁵ Hz ) = 4.14 eV From Einstein's photoelectric equation, the maximum kinetic energy is: K_ = E - W Rearranging for the work function W : W = E - K_ = 4.14 eV - 1.14 eV = 3.00 eV Answer: 3.00 eV

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