JEE MainMathematicsVector Algebra
Let a and b be two unit vectors such that the angle between them is 3 . If c is a non-zero vector such that a + 3 b is collinear with c and b + 4 c is collinear with a , then the value of 144| c |^2 is equal to
Options
- A16
- B10
- C7
- D13
Correct answer
D. 13
Step-by-step solution
Given that a + 3 b is collinear with c , we can write: a + 3 b = c (1) Also, b + 4 c is collinear with a , so: b + 4 c = a c = 4 a - 1 4 b (2) Substituting (2) into (1) gives: a + 3 b = ( 4 a - 1 4 b ) Rearranging the terms, we get: ( 1 - 4 ) a + ( 3 + 4 ) b = 0 Since a and b are non-collinear (the angle between them is 3 ), their coefficients must be zero: 3 + 4 = 0 = -12 1 - 4 = 0 1 - -12 4 = 0 = - 1 3 Using = -12 in equation (1) , we have: a + 3 b = -12 c c = - 1 12 ( a + 3 b ) Now, we find 144| c |^2 : 144| c |