JEE MainPhysicsSemiconductors
The digital signals A and B are applied as inputs to a logic gate, and the corresponding output signal is Y . The voltage levels of these signals during four consecutive time intervals are given below: Interval 1 : A = 0 V, B = 0 V, Y = 5 V Interval 2 : A = 5 V, B = 0 V, Y = 0 V Interval 3 : A = 0 V, B = 5 V, Y = 0 V Interval 4 : A = 5 V, B = 5 V, Y = 5 V Assuming 5 V represents logic '1' and 0 V represents logic '0'
Options
- AXNOR gate
- BXOR gate
- CAND gate
- DNOR gate
Correct answer
A. XNOR gate
Step-by-step solution
Let logic '1' correspond to 5 V and logic '0' correspond to 0 V. From the given data, we can construct the truth table for the logic gate: Interval 1: A = 0, B = 0 Y = 1 Interval 2: A = 1, B = 0 Y = 0 Interval 3: A = 0, B = 1 Y = 0 Interval 4: A = 1, B = 1 Y = 1 The output Y is 1 only when both inputs are identical. This corresponds to the truth table of an XNOR gate. Answer: XNOR gate