A toy water rocket contains 2 kg of water. It ejects all the water at a constant rate over a time interval of 4 s , experiencing an average thrust force of 15 N . The relative velocity of the ejected water is:

Step-by-step solution

The thrust force F exerted on the rocket due to the ejection of water is given by: F = v_ rel m t where v_ rel is the relative velocity of the ejected water, m is the mass of water ejected, and t is the time interval. Given: F = 15 N m = 2 kg t = 4 s Substitute the given values into the formula: 15 = v_ rel ( 2 4 ) 15 = v_ rel 0.5 v_ rel = 15 0.5 = 30 m s ⁻¹ Answer: 30 m s ⁻¹