JEE MainPhysicsDual Nature of Matter
A beam of light consisting of a mixture of red ( = 620 nm ), green ( = 500 nm ), and violet ( = 400 nm ) light is incident on a metal surface having a work function of 2.2 eV . The stopping potential required to reduce the photoelectric current to zero is: (Take hc = 1240 eV nm )
Options
- A0.9 V
- B0.28 V
- C1.18 V
- D0.2 V
Correct answer
A. 0.9 V
Step-by-step solution
The energy of an incident photon is given by E = hc . Calculating the photon energy for each color in the beam: For red light: E_R = 1240 620 = 2.0 eV For green light: E_G = 1240 500 = 2.48 eV For violet light: E_V = 1240 400 = 3.1 eV The work function of the metal is = 2.2 eV . Since E_R Both green and violet light have energies greater than the work function and will cause emission. The stopping potential V₀ is determined by the maximum kinetic energy of the emitted photoelectrons, which corresponds to the most e