JEE MainMathematicsVector Algebra
Let a = 2 i + j - 2 k and b = i + 3 j + k . If c is the vector component of b perpendicular to a , then the volume of the parallelepiped whose coterminous edges are a , b , and c a is
Options
- A0
- B99
- C90
- D9
Correct answer
C. 90
Step-by-step solution
The volume of the parallelepiped formed by the vectors a , b , and c a is given by the magnitude of their scalar triple product: V = |[ a , b , c a ]| = |( a b ) ( c a )| We are given that c is the component of b perpendicular to a . This means we can write b = p + c , where p is the component of b parallel to a . Now, consider the cross product a b : a b = a ( p + c ) = a p + a c Since p is parallel to a , a p = 0 , which gives a b = a c . Substitute this back into the volume expression: V = |( a c ) ( c a )| Sinc