JEE MainMathematicsVector Algebra
Let a vector a lie in the plane containing the vectors i + j and j + k . Let b be a vector obtained by rotating a by 90^ in the same plane. If the projection of vector b on the vector i - k is 6 , then the magnitude of the projection of vector a on the y-axis is equal to
Options
- A2
- B2
- C0
- D4
Correct answer
A. 2
Step-by-step solution
The normal vector n to the plane containing i + j and j + k is: n = ( i + j ) ( j + k ) = i - j + k Let a = a₁ i + a₂ j + a₃ k . Since a lies in the plane, a n = 0 : a₁ - a₂ + a₃ = 0 a₂ = a₁ + a₃ Vector b is obtained by rotating a by 90^ in the plane. Thus, b is perpendicular to both a and n , and | b | = | a | . This gives: b = n | n | a = 1 3 ( n a ) The projection of b on c = i - k is given as 6 . The magnitude of the projection is: | b c | | c | = 6 Now, evaluate the dot product b c : b ( i - k ) = 1 3 [( n a )