JEE MainPhysicsUnits and Dimensions
Match List I with List II. List I List II (A) Magnetic Flux (I) N A ⁻¹ m ⁻¹ (B) Magnetic Field (II) V s (C) Magnetic Permeability (III) s (D) Self Inductance (IV) T m A ⁻¹ Choose the correct answer from the options given below:
Options
- AA-IV, B-II, C-I, D-III
- BA-II, B-III, C-I, D-IV
- CA-I, B-II, C-IV, D-III
- DA-II, B-I, C-IV, D-III
Correct answer
D. A-II, B-I, C-IV, D-III
Step-by-step solution
Magnetic Flux ( ) is related to induced EMF by V = d dt , so its unit is V s . Magnetic Field ( B ) can be deduced from the magnetic force on a current-carrying wire F = I L B . Thus, B = F I L , which gives the unit N A ⁻¹ m ⁻¹ . Magnetic Permeability ( ₀ ) appears in Ampere's law, for example B = ₀ I 2 r . Rearranging gives ₀ = B r I , leading to the unit T m A ⁻¹ . Self Inductance ( L ) is defined by V = L di dt . Rearranging gives L = V i/t = ( V i ) t . Since V i is resistance ( ), the unit is s . Thus, the co