In a logic circuit, a buzzer is connected between the outputs of two logic gates. The first gate is an OR gate with inputs A and B, producing output Y₁ . The second gate is an AND gate with the same inputs A and B, producing output Y₂ . The buzzer sounds only when there is a potential difference between its terminals (i.e., Y₁ and Y₂ are at different logic levels). The inputs A and B are supplied with square waveform

Step-by-step solution

The buzzer sounds when there is a potential difference between its terminals, which means Y₁ Y₂ . The outputs of the gates are: Y₁ = A + B (OR gate) Y₂ = A B (AND gate) The condition Y₁ Y₂ is satisfied only when one input is HIGH and the other is LOW (i.e., A B ). If both are HIGH, Y₁=1 and Y₂=1 . If both are LOW, Y₁=0 and Y₂=0 . Let us analyze the inputs over the 6 ms period by breaking it into intervals: From t = 0 to 2 ms : A = 1, B = 1 A = B (Buzzer OFF) From t = 2 to 3 ms : A = 1, B = 0 A B (Buzzer ON for 1 ms