A Carnot engine with efficiency 50 % takes heat from a source at 600 ~K . To increase the efficiency to 70 % , keeping the temperature of the sink same, the new temperature of the source will be

Step-by-step solution

aligned & T _ H =600 k & =1- T _ C T _ H & but, = 1 2 .... ( Given: =50 %) & 1 2 =1- T _ C 600 & T _ C =300 ~K aligned (Given: =50 % ) With T _ C =300 ~K , the efficiency is increased to 70 % New temperature of the source will be T _ Hac _ a array ll =1- 300 ~T _ H _ ec 300 ~T _ H _ sew =1- 7 10 .( =70 %) T _ H _ ecw = 3000 3 =1000 ~K array