MHT CET20228 Aug 2022Evening ShiftPhysicsThermodynamicsActual
In the P-V diagram shown, there are two adiabatic parts of the same gas intersecting two isothermals at T₁ and T₂ . The ratio ( V_b V_a ) is equal to
Options
- A( V_c V_d )^2
- B( V_c V_d )
- C1 2 ( V_c V_d )
- D2 ( V_c V_d )
Correct answer
B. ( V_c V_d )
Step-by-step solution
For adiabatic process P V Y=C Ideal gas law states P V=n R T Dividing T V -1= constant above equations. Consider the diagram as follows: For path BC aligned & T₁=V_b^ -1 =T₂= c V -1 & ( V_b V_c )^ Y-1 = T₂ T₁ ---(1) aligned Now, for path DA. aligned & T₂= d V -1=T₁= a V -1 & ( V_a V_d )^ -1 = T₂ T₁ --(2) aligned aligned & V_b V_c = V_a V_d & V_b V_a = V_c V_d aligned Option (B) is correct.