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AP EAMCET202018 Sep 2020Evening ShiftMathematicsCircleActual

The equation of the normal to the circle (x^2+y^2=16 ) at the point ( ( 1 3 , 1 3 ) ) is

Options

  1. A(x+y=0 )
  2. B(x-y= 3 4 )
  3. C(x-y=0 )
  4. D(x+y= 3 4 )

Correct answer

C. (x-y=0 )

Step-by-step solution

Centre (C=(0,0) ) (P= ( 1 3 , 1 3 ) ) Since, every normal passes through centre ( ) Equation of Normal (= ) Equation of ( CP ) ( array ll & y-0= 1 3 -0 1 3 -0 (x-0) y=1 x & x-y=0 array ) Hence, option (c) is correct.

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