MHT CET2019Evening ShiftPhysicsUnits and DimensionsActual
The force ‘F’ acting on a body of density ‘d’ are related by the reflection F = y d . The dimensions of ‘y’ are
Options
- AL - 1 2 M 3 2 T - 2
- BL - 1 M 1 2 T - 2
- CL - 1 M 3 2 T - 2
- DL - 1 2 M 1 2 T - 2
Correct answer
A. L - 1 2 M 3 2 T - 2
Step-by-step solution
The dimension of force F = M L T - 2 And density d = M L - 3 T 0 From the given relation, F = y d ⇒ y = F d Substituting the above dimensions, we get y = F d 1 / 2 = M L T - 2 M L - 3 T 0 1 / 2 = M 3 / 2 L - 1 2 T - 2