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MHT CET202620 April 2026Morning ShiftPhysicsWave OpticsActual

In an interference experiment, the m^ th bright fringe for light of wavelength ₁ coincides with the n^ th dark fringe for light of wavelength ₂ . The ratio ₂ ₁ is

Options

  1. Am n-1
  2. Bm (2n-1)
  3. C2m (2n-1)
  4. D2m (2n+1)

Correct answer

C. 2m (2n-1)

Step-by-step solution

The position of the m^ th bright fringe for light of wavelength ₁ is given by: y₁ = m ₁ D d The position of the n^ th dark fringe for light of wavelength ₂ is given by: y₂ = (2n - 1) ₂ D 2d Since the two fringes coincide, we equate their positions ( y₁ = y₂ ): m ₁ D d = (2n - 1) ₂ D 2d m ₁ = (2n - 1) ₂ 2 ₂ ₁ = 2m 2n - 1 Answer: 2m (2n-1)

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