In biprism experiment, the maximum intensity is I₀ . If the path difference between the two interfering waves is 3 , then intensity at the point on the screen is [ 30^ = 60^ = 0.5 , 60^ = 30^ = 3 /2 ]

Step-by-step solution

The phase difference is related to the path difference x by the relation: = 2 x Given x = 3 , the phase difference is: = 2 3 = 2 3 The intensity I at a point on the screen is given by: I = I₀ ^2 ( 2 ) Substituting the value of : I = I₀ ^2 ( 2 /3 2 ) = I₀ ^2 ( 3 ) Since ( 3 ) = 60^ = 1 2 , we get: I = I₀ ( 1 2 )^2 = I₀ 4