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MHT CET202619 April 2026Evening ShiftPhysicsWave OpticsActual

A ray of light is incident at polarising angle on air-glass interface. If _a and _g are the wavelengths of light in air and glass respectively then

Options

  1. A_a = _g
  2. B_g = _a
  3. C_a = _g ^2
  4. D_g = _a ^2

Correct answer

B. _g = _a

Step-by-step solution

According to Brewster's law, the refractive index of glass with respect to air is given by = , where is the polarising angle. The refractive index is also equal to the ratio of the wavelength of light in air to the wavelength of light in the medium: = _a _g Equating the two expressions for , we get: _a _g = _g = _a _g = _a Answer: _g = _a

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