In Young's double slit experiment, the distance between the slits is 3 mm and the slits are 2m away from the screen. Two interference patterns can be obtained on the screen due to light of wavelength 480 nm and 600 nm respectively. The separation on the screen between the 5^ th order bright fringes on two interference patterns is

Step-by-step solution

Given: d = 3 mm = 3 10⁻³ m D = 2 m ₁ = 480 nm = 480 10⁻⁹ m ₂ = 600 nm = 600 10⁻⁹ m The position of the n^ th order bright fringe is given by y_n = n D d . The separation between the 5^ th order bright fringes of the two patterns is: y = y_ 5,2 - y_ 5,1 = 5 D d ( ₂ - ₁) Substituting the given values: y = 5 2 3 10⁻³ (600 - 480) 10⁻⁹ y = 10 3 10⁻³ 120 10⁻⁹ y = 400 10⁻⁶ m y = 4 10⁻⁴ m Answer: 4 10⁻⁴ , m