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MHT CET202615 April 2026Evening ShiftPhysicsWave OpticsActual

Light of wavelength is incident on a single slit of width 'a' and the distance between slit and screen is 'D'. In diffraction pattern, if slit width is equal to the width of the central maximum then 'D' is equal to

Options

  1. Aa
  2. Ba^2
  3. Ca 2
  4. Da^2 2

Correct answer

D. a^2 2

Step-by-step solution

The linear width of the central maximum in a single slit diffraction pattern is given by 2 D a , where is the wavelength, D is the distance between the slit and the screen, and a is the slit width. According to the given condition, the width of the central maximum is equal to the slit width. Therefore, a = 2 D a Rearranging the equation to solve for D , we get: D = a^2 2 Answer: a^2 2

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