A double slit experiment is immersed in water of refractive index 1.33 . The slit separation is 1 mm, distance between slit and screen is 1.33 m. The slits are illuminated by light of wavelength 6300 . The fringe width is

Step-by-step solution

When the double slit experiment is immersed in a liquid of refractive index , the wavelength of light in the medium becomes ' = . The fringe width is given by the formula: = ' D d = D d Given values are: = 6300 = 6300 10⁻¹⁰ m D = 1.33 m = 1.33 d = 1 mm = 10⁻³ m Substituting these values into the formula: = 6300 10⁻¹⁰ 1.33 1.33 10⁻³ = 6300 10⁻¹⁰ 10⁻³ = 6300 10⁻⁷ m = 6.3 10⁻⁴ m Answer: 6.3 10⁻⁴ m