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MHT CET202611 April 2026Morning ShiftPhysicsWave OpticsActual

Two light waves amplitudes in the ratio 3:1 produce interference. The ratio of the maximum to minimum intensity is

Options

  1. A9 : 4
  2. B16 : 9
  3. C3 : 2
  4. D4 : 1

Correct answer

D. 4 : 1

Step-by-step solution

Let the amplitudes of the two light waves be A₁ and A₂ . Given A₁ A₂ = 3 1 The maximum intensity I_ max is proportional to (A₁ + A₂)^2 and the minimum intensity I_ min is proportional to (A₁ - A₂)^2 . I_ max I_ min = (A₁ + A₂)^2 (A₁ - A₂)^2 Substituting the ratio of amplitudes: I_ max I_ min = (3 + 1)^2 (3 - 1)^2 = 16 4 = 4 1 The ratio of maximum to minimum intensity is 4 : 1 . Answer: 4 : 1

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