A ray of light is incident of the surface of a glass plate at an angle of incidence equal to Brewster's angle . If denotes the refractive index of glass w.r.t. air, then what will be the angle between reflected and refracted rays?

Step-by-step solution

According to Brewster's law, when a ray of light is incident at Brewster's angle , the refractive index of the medium is given by = . By Snell's law, = r , where r is the angle of refraction. Equating the two expressions for , we get: = r r = = (90^ - ) r = 90^ - The angle of reflection is equal to the angle of incidence, so the angle of reflection is . The angle between the reflected and refracted rays is 180^ - ( + r) . Substituting the value of r , we get: 180^ - ( + 90^ - ) = 90^ Thus, the reflected and refract