In Young's double slit experiment, the intensity on screen at a point, where path difference is 4 is K 4 . The intensity at a point when path difference is ' ' will be [ 2 =0, 2 =1 ]

Step-by-step solution

The intensity at a point in Young's double-slit experiment is given by I = I_ ^2 ( 2 ) , where the phase difference relates to path difference by = 2 x . When the path difference is x₁ = 4 , the intensity is I₁ = K 4 . The corresponding phase difference is ₁ = 2 4 = 2 . Substituting into the intensity formula yields I₁ = I_ ^2 ( 4 ) = I_ 2 . Equating with the given intensity gives I_ 2 = K 4 , so I_ = K 2 . For a path difference of x₂ = , the phase difference becomes ₂ = 2 . The intensity is then I₂ = I_ ^2( ) = I_