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MHT CET202527 Apr 2025Evening ShiftPhysicsWave OpticsActual

In a biprism experiment, the distance of the second dark fringe from the central fringe is 3 mm . The distance of the sixth bright fringe from the central fringe is

Options

  1. A12 mm
  2. B8 mm
  3. C6 mm
  4. D4 mm

Correct answer

A. 12 mm

Step-by-step solution

The position of the second dark fringe is x_ dark,2 = (2 - 1 2 ) D d = 3 2 D d . Given x_ dark,2 = 3 mm , solve for the fringe width: D d = 3 2 3 = 2 mm . For the sixth bright fringe: x_ bright,6 = 6 2 mm = 12 mm . Final answer: 12 mm

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