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MHT CET202525 Apr 2025Morning ShiftPhysicsWave OpticsActual

A single slit diffraction pattern is formed with light of wavelength 6384 Å . The second secondary maximum for this wavelength coincides with the third secondary maximum in the pattern for light of wavelength ' ₀^ . The value of ' ₀^ is

Options

  1. A4242 Å
  2. B4560 Å
  3. C5474 Å
  4. D6384 Å

Correct answer

B. 4560 Å

Step-by-step solution

The condition for a secondary maximum in single-slit diffraction is a = (m + 1 2 ) , where a is the slit width and m is the order starting from 1. For wavelength = 6384 Å at m=2 : a ₁ = 5 2 For wavelength ₀ at m=3 : a ₂ = 7 2 ₀ Since ₁ = ₂ , the expressions are equal: 5 2 = 7 2 ₀ Solving yields ₀ = 5 7 = 5 7 6384 = 4560 Å. Final answer: 4560 Å

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