In Young's double slit experiment, the distance between screen and aperture is 1 m . The slit width is 2 mm . Light of 6000 Å is used. If a thin glass plate ( =1.5 ) of thickness 0.04 mm is placed over one of the slits, then there will be a lateral displacement of the fringes by

Step-by-step solution

The lateral displacement of the fringes in Young's double-slit experiment due to a thin glass plate over one slit is given by: x = D d ( - 1)t Substituting the given values D = 1 m , d = 2 10⁻³ m , = 1.5 , and t = 4 10⁻⁵ m , we compute: x = 1 2 10⁻³ (1.5 - 1) (4 10⁻⁵) = 0.5 4 10⁻⁵ 2 10⁻³ = 2 10⁻⁵ 2 10⁻³ = 1 10⁻² m This corresponds to a displacement of 1 cm . Final answer : 1 cm