MHT CET202520 Apr 2025Morning ShiftPhysicsWave OpticsActual
In Young's double slit experiment, for the n th dark fringe ( n=1,2,3 ) the phase difference of the interfering waves in radian will be
Options
- An 2
- B(2 n+1)
- C(2 n-1)
- D(2 n-1) 2
Correct answer
C. (2 n-1)
Step-by-step solution
The phase difference for the n th dark fringe follows from the condition for destructive interference, where the path difference is x = (2n - 1) 2 for n = 1, 2, 3, Since phase difference relates to path difference by = 2 x , substituting gives = 2 (2n - 1) 2 . Simplifying yields = (2n - 1) radians. Final answer: C