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AP EAMCET202017 Sep 2020Evening ShiftMathematicsCircleActual

The polar of ((1,-2) ) with respect to (x^2+y^2-10 x-10 y+25=0 ) is

Options

  1. A(4 x+7 y+30=0 )
  2. B(4 x+7 y-30=0 )
  3. C(4 x-7 y+30=0 )
  4. D(x+y=0 )

Correct answer

B. (4 x+7 y-30=0 )

Step-by-step solution

Given circle is, (x^2+y^2-10 x-10 y+25=0 ) Given point ' (P ) ' is ((1,-2) ) Equation of polar of point (P ) with respect to circle is, ( aligned & x 1+y(-2)-10 ( x+1 2 )-10 ( y-2 2 )+25=0 & x-2 y-5(x+1)-5(y-2)+25=0 & x-2 y-5 x-5-5 y+10+25=0 & -4 x-7 y+30=0 & 4 x+7 y-30=0 aligned )

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