MHT CET202415 May 2024Morning ShiftPhysicsWave OpticsActual
In biprism experiment, the fringe width is 0.6 mm . The distance between 6^ th dark fringe and 8^ th bright fringe on the same side of central bright fringe is
Options
- A6 mm
- B4 mm
- C1.5 mm
- D0.9 mm
Correct answer
C. 1.5 mm
Step-by-step solution
For 8^ th bright fringe, x ₈=8 X For 6^ th dark fringe, aligned & x₆= (6- 1 2 ) X=5.5 X & x₈-x₆=8 X-5.5 X=2.5 X & x₈-x₆=2.5 0.6=1.5 ~mm aligned