In Young's double slit experiment, 'I' is the minimum intensity and ' I ₁ ' is the intensity at a point where the path difference is 4 where ' ' is the wavelength of light used. The ratio I / I₁ is (Intensities of the two interfering waves are same) ( 0^ =1, 90^ =0 )

Step-by-step solution

- Concept: At / 4 path difference, the phase difference is / 2 radians. The resultant intensity for two waves of equal amplitude interfering with a phase difference is I=4 I₀ ^2( / 2) . - Calculation: = / 2 leads to I=4 I₀ ^2( / 4)=4 I₀ (1 / 2 )^2=2 I₀ . - Since I₁ (dark fringe) is 0 , comparing intensities is not straightforward, but given that minimum intensity (I₁ ) typically represents a baseline or zero in the theoretical model, the scenario described doesn't make practical sense. It's a conceptual error as I₁