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AP EAMCET202017 Sep 2020Morning ShiftMathematicsCircleActual

If one end of diameter of the circle (x^2+y^2-4 x-6 y+11=0 ) is ((3,4) ), then the other end of the diameter is

Options

  1. A((0,1) )
  2. B((1,1) )
  3. C((1,2) )
  4. D((1,0) )

Correct answer

C. ((1,2) )

Step-by-step solution

Given, circle (x^2+y^2-4 x-6 y+11=0 ) ( ) Centre (=(2,3) ) One end diameter (=(3,4) ) Let other end be ((h, k) ) So, ( h+3 2 =2, k+4 2 =3 ) ( h=1, k=2 )

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