In a diffraction pattern due to single slit of width ' a ', the first minimum is observed at an angle 30^ when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle [ 30= 1 2 ]

Step-by-step solution

For n ^ th secondary minimum, path difference = a _ n = n and for n ^ th secondary maximum, path difference =a _n=(2 n+1) 2 For 1^ st minimum, a 30^ = ...(i) For 2^ nd maximum, a _n=(2+1) 2 ...(ii) Dividing equations (i) by equation (ii), 1 / 2 _n = 2 3 _n= ⁻¹ ( 3 4 )