MHT CET20249 May 2024Evening ShiftPhysicsWave OpticsActual
In the Young's double slit experiment, the intensity at a point on the screen, where the path difference is ( = wavelength ) is . The intensity at a point where the path difference is / 3 , will be . 3 =1 / 2 ]
Options
- A/ 2
- B4
- C/ 8
Correct answer
C. / 8
Step-by-step solution
The intensity is given by I =4 I ₀ ^2 2 Maximum intensity =4 I ₀ when =0 when path difference is 3 , = 2 3 I= ^2 2 3 = (- 1 2 )^2= 4