MHT CET20249 May 2024Evening ShiftPhysicsWave OpticsActual
The fringe width in an interference pattern is ' X '. The distance between the sixth dark fringe from one side of central bright band to the fourth bright fringe on other side is
Options
- A1.5 X
- B2 X
- C5.5 X
- D9.5 X
Correct answer
D. 9.5 X
Step-by-step solution
Fringe width is given by, W= D d =X ...(given) Position of 4^ th bright fringe =n D d =4 X aligned Position of 6^ th dark fringe & =(2 n -1) D 2 ~d & =(2(6)-1) X 2 & =5.5 X aligned Total distance =(4+5.5) X =9.5 X