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MHT CET20249 May 2024Evening ShiftPhysicsWave OpticsActual

In Young's double slit experiment using monochromatic light of wavelength ' ', the maximum intensity of light at a point on the screen is ' K ' units. The intensity of light at a point where the path difference is 6 , is ( 60^ = 30^ =0.5, 60^ = 30^ = 3 / 2 ) .

Options

  1. A3 ~K 4
  2. BK 4
  3. CK 2
  4. DK

Correct answer

A. 3 ~K 4

Step-by-step solution

The intensity is given by I =4 I ₀ ^2 2 ...(i) Maximum intensity K =4 I ₀ when =0 when path difference is 6 , aligned & = 2 path difference = 3 ...(ii) & I=K ^2 ( 6 )=K ( 3 4 )= 3 K 4 aligned ...[From(i) and (ii)]

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