MHT CET20249 May 2024Morning ShiftPhysicsWave OpticsActual
Two wavelength 590 nm and 596 nm of sodium light are used one after other, to study the diffraction taking place at a single slit of aperture 2.4 mm . The distance between the slit and screen is 2 m . The separation between the positions of first secondary maximum of the diffraction pattern obtained in the two cases is
Options
- A7.5 10⁻⁶ ~m
- B7.5 10⁻⁹ ~m
- C2.5 10⁻⁶ ~m
- D5.0 10⁻⁶ ~m
Correct answer
A. 7.5 10⁻⁶ ~m
Step-by-step solution
The first secondary maximum in a single slit diffraction pattern is obtained at =(2 n +1) 2 a = 3 2 a for small angles, = array ll & 3 2 a = x D x= 3 D 2 a & x= 3 D ( ₂- ₁ ) 2 d = 3 2 (596-590) 10⁻⁹ 2 2.4 10⁻³ & x=7.5 10⁻⁶ m array